CAPM · Question #385
The project manager has following information about duration for an activity: Most likely [tM] - 15 days Pessimistic [tP] - 20 days Optimistic [tO] - 10 days What is the estimated duration of this act
The correct answer is B. 15 days. Using the triangular distribution formula - a simple average of the three estimates - yields (10 + 15 + 20) / 3 = 15 days.
Question
- Most likely [tM] - 15 days
- Pessimistic [tP] - 20 days
- Optimistic [tO] - 10 days What is the estimated duration of this activity, according to the triangular distribution technique?
Options
- A10 days
- B15 days
- C12.5 days
- D5 days
How the community answered
(31 responses)- A6% (2)
- B77% (24)
- C3% (1)
- D13% (4)
Why each option
Using the triangular distribution formula - a simple average of the three estimates - yields (10 + 15 + 20) / 3 = 15 days.
10 days is the optimistic estimate (tO) alone and is not the result of applying any three-point estimation formula combining all three input values.
The triangular distribution formula is (tO + tM + tP) / 3 = (10 + 15 + 20) / 3 = 45 / 3 = 15 days. Unlike the PERT beta distribution formula - (tO + 4tM + tP) / 6 - which weights the most likely estimate four times, the triangular distribution treats all three estimates equally as a simple arithmetic mean, producing 15 days in this case.
12.5 days does not result from any standard three-point estimation formula - neither triangular nor PERT beta - applied to the given values of 10, 15, and 20.
5 days represents the difference between the optimistic and most likely estimates and has no basis as a duration estimate under any recognized three-point distribution technique.
Concept tested: Triangular distribution three-point estimation calculation
Source: https://www.pmi.org/pmbok-guide-standards/foundational/pmbok
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