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PMI-SP · Question #16

John works as a project manager of the NHQ Project. He has created the project network diagram as shown in the figure: Based on the project network diagram, how much float is available for Activity…

The correct answer is A. Zero. The path of ABEHJ will take 22 days to complete and cannot exceed 28 days or else the project will be late. If Activity B takes four additional days and Activity E takes two additional days, this adds (4+2= 6) six days to the path, bringing the path's duration to exactly (22+6…

Schedule Monitoring and Controlling

Question

John works as a project manager of the NHQ Project. He has created the project network diagram as shown in the figure:

Based on the project network diagram, how much float is available for Activity H if Activity B is delayed by four days and Activity E is delayed by two days?

Exhibit

PMI-SP question #16 exhibit

Options

  • AZero
  • BOne
  • CFour
  • DFive

How the community answered

(63 responses)
  • A
    63% (40)
  • B
    21% (13)
  • C
    5% (3)
  • D
    11% (7)

Explanation

The path of ABEHJ will take 22 days to complete and cannot exceed 28 days or else the project will be late. If Activity B takes four additional days and Activity E takes two additional days, this adds (4+2= 6) six days to the path, bringing the path's duration to exactly (22+6 = 28) days. There is no available float left for Activity D or H. Float or total float (TF) is the total amount of time that a schedule activity may be delayed from its early start date without delaying the project finish date, or violating a schedule constraint. It is calculated by using the critical path method technique and determining the difference between the early finish dates and late finish dates. Answer options B, C, and D are incorrect. There is no float available because the path's duration has increased to 28 days.

Topics

#float calculation#network diagram#activity delays#critical path

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