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352-001 · Question #80
352-001 Question #80: Real Exam Question with Answer & Explanation
The correct answer is B: ones in which the reported distance is less than the feasible distance. EIGRP uses the Feasibility Condition to guarantee loop-free alternate paths: a neighbor's Reported Distance must be strictly less than the local router's current Feasible Distance.
Question
When a router running EIGRP considers alternate paths, which ones will it consider loop-free?
Options
- Aones in which the reported distance is equal to the feasible distance
- Bones in which the reported distance is less than the feasible distance
- Cones in which the feasible distance is the same as the best possible route
- Dones in which the reported distance is the same as the metric of the best possible path
Explanation
EIGRP uses the Feasibility Condition to guarantee loop-free alternate paths: a neighbor's Reported Distance must be strictly less than the local router's current Feasible Distance.
Common mistakes.
- A. An RD equal to the FD does not satisfy the Feasibility Condition (the condition requires strictly less than, not equal to), so equal-RD neighbors are not guaranteed to be loop-free and are not classified as Feasible Successors.
- C. A route whose feasible distance equals the best possible route describes the Successor (current best path), not the criteria used to identify loop-free alternate Feasible Successors.
- D. An RD equal to the metric of the best path means RD equals FD, which fails the strict less-than requirement of the Feasibility Condition and does not guarantee a loop-free path.
Concept tested. EIGRP Feasibility Condition for loop-free alternates
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