v = 1 def fun(): global v v = 2 return v print(v)

The correct answer is B. 1. Option B (1) is correct because fun() is never called - it is only defined. Since the function never executes, the global v declaration and the reassignment v = 2 inside it never run, so v retains its original value of 1 when print(v) is reached. Why the distractors are wrong…

Question

v = 1
def fun():
global v
v = 2
return v
print(v)

Options

ANone
B1
CThe program will cause an error.
D2

How the community answered

(36 responses)

A
17% (6)
B
72% (26)
C
3% (1)
D
8% (3)

Explanation

Option B (1) is correct because fun() is never called - it is only defined. Since the function never executes, the global v declaration and the reassignment v = 2 inside it never run, so v retains its original value of 1 when print(v) is reached.

Why the distractors are wrong:

D (2) is the most common trap: readers assume the global keyword and v = 2 inside the function take effect just by being defined, but function bodies only execute when called.
A (None) would only be correct if print(fun()) were used and the function returned nothing - fun() does return a value, but again, it's never invoked.
C (error) is incorrect because the code is syntactically valid and runs without exception.

Memory tip: Ask yourself, "Is the function called or just defined?" A function definition (def) is just a blueprint - no code inside it runs until you invoke it with parentheses (e.g., fun()). If you don't see the call, the function's body is invisible to the program flow.

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