What is the expected output of the following code? ``python def func1(x): return str(x) def func2(x): return str(2 * x) print(func1(1) + func2(2)) ``

Question

def func1(x):
 return str(x)

def func2(x):
 return str(2 * x)

print(func1(1) + func2(2))

Options

• A3
• B5
• CThe code is erroneous.
• D14

• A
  12% (3)
• B
  4% (1)
• C
  4% (1)
• D
  80% (20)

Explanation

D is correct because both functions return strings via str(), so the + operator performs string concatenation, not addition. func1(1) returns "1" and func2(2) returns str(2 * 2) = "4", giving "1" + "4" = "14".

Why the distractors fail:

• A (3) assumes numeric addition of the inputs (1 + 2), ignoring that func2 doubles its argument before converting.
• B (5) assumes numeric addition of the computed values (1 + 4), forgetting that str() makes them strings, not integers.
• C is wrong because the code is perfectly valid Python - it runs without error.

Memory tip: Whenever you see str() in a function return, mentally replace + with "glue" instead of "add." Strings glue side-by-side ("1" glued to "4" = "14"), they don't sum numerically.

No community discussion yet for this question.