What is the expected output of the following code? ``python x = True y = False z = False if x or y and z: print('TRUE') else: print('FALSE') ``

Question

x = True
y = False
z = False

if x or y and z:
 print('TRUE')
else:
 print('FALSE')

Options

• AThe code is erroneous.
• BTRUE
• CFALSE
• DNone of the above.

• A
  13% (7)
• B
  75% (39)
• C
  8% (4)
• D
  4% (2)

Explanation

Option B is correct because Python's operator precedence rules evaluate and before or, so the expression x or y and z is parsed as x or (y and z). Since y and z evaluates to False and False = False, the full expression becomes True or False, which is True - triggering the if branch and printing TRUE.

Option A is wrong because the code is perfectly valid Python - no syntax or runtime errors occur. Option C is wrong because a beginner might mistakenly read the expression left-to-right as (x or y) and z, which would yield True and False = False, but that's not how Python evaluates it. Option D is wrong because B is a valid correct answer.

Memory tip: Think of and as multiplication and or as addition - in math, multiplication always happens before addition (2 + 3 × 0 = 2, not 0). The same logic applies here: and binds tighter, so evaluate it first before or.

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