What is the output of the following code? a = 10 b = 20 c = a > b print(not(c))

The correct answer is D. True. a > b evaluates to False because 10 is not greater than 20, so c = False. Applying not() to False flips it to True, which is what gets printed - making D correct. Option B (False) is wrong because it confuses c with not(c), stopping one step too early. Option A is wrong because…

Question

What is the output of the following code?
a = 10
b = 20
c = a > b
print(not(c))

Options

AThe program will cause an error.
BFalse
CNone
DTrue

How the community answered

(20 responses)

A
5% (1)
B
5% (1)
C
15% (3)
D
75% (15)

Explanation

a > b evaluates to False because 10 is not greater than 20, so c = False. Applying not() to False flips it to True, which is what gets printed - making D correct. Option B (False) is wrong because it confuses c with not(c), stopping one step too early. Option A is wrong because the code is syntactically valid Python with no errors. Option C (None) is wrong because print() outputs the value of its argument, not None - it only returns None, which is never displayed here. Memory tip: Think of not as a light switch - it flips the boolean to its opposite, so not(False) is always True.

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