What is the output of the following snippet? ``python def fun(x): x += 1 return x x = 2 x = fun(x + 1) print(x) ``

Question

def fun(x):
 x += 1
 return x

x = 2
x = fun(x + 1)
print(x)

Options

• A4
• B5
• CThe code is erroneous.
• D3

• A
  79% (38)
• B
  2% (1)
• C
  13% (6)
• D
  6% (3)

Explanation

Option A (4) is correct because Python evaluates x + 1 first (2 + 1 = 3) before passing it to fun, then fun adds 1 more (3 + 1 = 4) and returns that value, which overwrites x.

B (5) is wrong - this would only be correct if x were incremented twice from its base value of 2 plus 2 extra, which misreads the call as fun(x) + 1 or double-counts the addition.

D (3) is wrong - this mistakes fun(x + 1) for fun(x), missing that the argument passed in is already 3, not 2.

C is wrong - the code runs without errors; Python has no issue with reusing the variable name x inside the function, since the inner x is a local copy.

Memory tip: Always evaluate the argument expression first, then the function body - think of it as two separate "+1" steps happening in sequence: one before the call, one inside it.

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