Which two conditions must be met for EIGRP to maintain an alternate loop-free path to a remote network? (Choose two.)

The EIGRP feasibility condition requires that a neighbor's Reported Distance (RD) be strictly less than the local router's current Feasible Distance (FD) to the destination, which mathematically guarantees the neighbor is not downstream and cannot create a routing loop as defined by DUAL.

A neighbor's RD being higher than the local FD fails the feasibility condition, meaning that neighbor could be a downstream router and is explicitly excluded as a feasible successor to prevent loops.

The feasibility condition is mandatory and non-optional - it is the core mathematical guarantee within DUAL that ensures all feasible successors are loop-free without requiring full topology recalculation.

This reverses the relationship: the feasibility check compares the candidate neighbor's RD against the local FD, not the successor's FD against a local RD, so this condition does not represent valid EIGRP logic.

A feasible successor must actually exist in the EIGRP topology table for an alternate loop-free path to be available; if no feasible successor is present, EIGRP must go active and send queries throughout the network to find a new successor.