350-001 · Question #175
350-001 Question #175: Real Exam Question with Answer & Explanation
The correct answer is C: Gi3/7. IP 225.230.57.199 will become MAC 0100.5ee6.39c7, so the interfaces G3/7, F6/28 and F7/20 will receive the traffic. Mac address 0100.5e66.39c7 is accessible via Gi3/4, Gi3/7, Fa4/10, Fa4/14, Fa7/31, and Fa7/40. So options C and E i.e., Gi3/7 & Fa4/14 are the correct answers. Firs
Question
Exhibit
Options
- AFa6/28
- BFa7/20
- CGi3/7
- DFa4/2
- EFa4/14
- FFa4/38
- GFa6/28
- HFa5/7
Explanation
IP 225.230.57.199 will become MAC 0100.5ee6.39c7, so the interfaces G3/7, F6/28 and F7/20 will receive the traffic. Mac address 0100.5e66.39c7 is accessible via Gi3/4, Gi3/7, Fa4/10, Fa4/14, Fa7/31, and Fa7/40. So options C and E i.e., Gi3/7 & Fa4/14 are the correct answers. First thing is to convert the IP address to binary so: 225.230.57.199 in binary is 11100001 11100110 00111001 11000111. Then put the first 6 hex characters in front of the binary address and remove the first 4 bits (which are always 1110) this is the IEEE OUI for layer 2 multicast addressing 0100.5e | 0001 11100110 00111001 11000111. Then we "always" change the next 5 bits to a binary 0 (which leaves us with 24 bits for the conversion to hex) 0100.5e | 01100110 00111001 11000111 This leaves you with 24 bits to convert into hex from binary. Thus 01100110 00111001 11000111 = 66.39.c7 and the question asks which interfaces listed are forwarding this group... All of the following interfaces below are forwarding this: Gi3/4, Gi3/7, Fa4/10, Fa4/14, Fa7/31, Fa7/40 But only 2 are listed in the multiple choice:
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