312-49 · Question #412
A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the attacker…
The correct answer is A. The attacker has conducted a network sweep on port 111. The Snort log explicitly shows a UDP packet sent from 211.185.125.124:789 to 172.16.1.103:111. Port 111 is the Sun RPC portmapper service. The packet is destined for a different host (103, not 108), which indicates the attacker is probing/sweeping port 111 across the subnet…
Question
A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the attacker by studying the log. Please note that you are required to infer only what is explicit in the excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting, basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.) TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF A* Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32 TCP Options (3) => NOP NOP TS: 23678634 2878772 =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= += 03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111 UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84 Len: 64 01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................ 00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................ 00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................ 00 00 00 11 00 00 00 00 ........ =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= += 03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773 UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104 Len: 1084 47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............ 00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ............... 3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.^.....localhost =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+= +=+=+ 03/15-20:21:36.539731 211.185.125.124:4450 -> 172.16.1.108:39168 TCP TTL:43 TOS:0x0 ID:31660 IpLen:20 DgmLen:71 DF AP Seq: 0x9C6D2BFF Ack: 0x59606333 Win: 0x7D78 TcpLen: 32 TCP Options (3) => NOP NOP TS: 23679878 2880015 63 64 20 2F 3B 20 75 6E 61 6D 65 20 2D 61 3B 20 cd /; uname -a; 69 64 3B id;
Options
- AThe attacker has conducted a network sweep on port 111
- BThe attacker has scanned and exploited the system using Buffer Overflow
- CThe attacker has used a Trojan on port 32773
- DThe attacker has installed a backdoor
How the community answered
(31 responses)- A81% (25)
- B3% (1)
- C6% (2)
- D10% (3)
Explanation
The Snort log explicitly shows a UDP packet sent from 211.185.125.124:789 to 172.16.1.103:111. Port 111 is the Sun RPC portmapper service. The packet is destined for a different host (103, not 108), which indicates the attacker is probing/sweeping port 111 across the subnet. There is no evidence in this excerpt of a buffer overflow exploit (B), a Trojan on port 32773 (C), or a backdoor installation (D) - the question instructs you to infer only what is explicitly shown.
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