When planning a telecommunication termination area, what is the estimated space needed to terminate 144 strands of optical fiber?

Question

Options

• A6350.01 mm2 (250 in2)
• B7315.21 mm2 (288 in2)
• C8890.01 mm2 (350 in2)
• D10972.82 mm2 (432 a)
• E14376.43 mm2 (566 in2)

• B
  79% (15)
• C
  11% (2)
• D
  5% (1)
• E
  5% (1)

Explanation

Option B is correct because the standard planning guideline for optical fiber termination space is 2 square inches per fiber strand. Multiplying 144 strands by 2 in² gives exactly 288 in², matching answer B. Option A (250 in² / ~1.74 in² per strand) underestimates the required space and would leave insufficient room for proper cable management and bend radius protection. Options C (350 in²), D (432 in²), and E (566 in²) all exceed the standard allocation, representing common overestimates that waste valuable rack or cabinet space without providing any practical benefit.

Memory tip: Think "2 square inches per strand" as your base formula. For 144 fibers, that is 144 x 2 = 288 in². If you remember that a standard 12-strand fiber panel needs 24 in², you can scale up (12 panels x 24 in² = 288 in²) as a cross-check.

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