What is the expected output of the following code? print(3 * "abc" + 'xyz')

Question

Options

• A3abcxyz
• Babcabcxyzxyz
• Cabcabcabcxyz
• Dabcxyzabcxyzabcxyz

• A
  6% (2)
• B
  9% (3)
• C
  82% (27)
• D
  3% (1)

Explanation

Option C is correct because Python's * operator on a string repeats it - 3 * "abc" produces "abcabcabc" - and then + concatenates "xyz" to the end, giving "abcabcabcxyz". Option A (3abcxyz) is wrong because 3 * does not prepend a numeric digit; it repeats the string. Option B (abcabcxyzxyz) incorrectly assumes "xyz" also gets repeated, which it does not - repetition only applies to "abc". Option D (abcxyzabcxyzabcxyz) mistakes operator precedence: * binds to "abc" alone, not to the entire "abc" + 'xyz' expression.

Memory tip: Think of * as a copy machine - 3 * "abc" makes 3 copies of "abc" first, then + staples "xyz" onto the end exactly once.

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