Consider the following list. data = [1, 5, 10, 19, 55, 30, 99] Which of the code snippets below would produce a new list like the following? [1, 5, 10, 99]

Question

Options

• Adata.pop(5) data.pop(19) data.pop(55)
• Bdata.pop(1) data.pop(3) data.pop(4) data.pop(6)
• CNone of the above.
• Ddata.pop(5) data.remove(19) data.remove(55)
• Edata.remove(5) data.remove(19) data.remove(55)

• A
  4% (2)
• B
  2% (1)
• C
  9% (4)
• D
  83% (38)
• E
  2% (1)

Explanation

Option D works because it correctly combines pop() and remove() - two methods that operate differently: pop(index) removes an element by its position, while remove(value) removes an element by its value. Calling data.pop(5) removes the element at index 5 (which is 30), leaving [1, 5, 10, 19, 55, 99], then data.remove(19) and data.remove(55) remove those values by value, yielding [1, 5, 10, 99].

Why the distractors fail:

• A passes values (19, 55) to pop(), which expects indices - data.pop(19) raises an IndexError since the list only has 7 elements.
• B pops index 1 (which removes 5, a value we need to keep), and data.pop(6) raises an IndexError after the list has already shrunk.
• C is wrong because D is valid.
• E calls data.remove(5), which removes the value 5 - something we need to keep - leaving 30 in the list and producing [1, 10, 30, 99] instead.

Memory tip: Think of it as "pop the position, remove the value" - pop() takes an index number like an array slot, remove() takes the actual element you want gone.

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