What is the expected output of the following code? data = [[0, 1, 2, 3] for i in range(2)] print(data[2][0])

Question

Options

• AThe code is erroneous.
• B2
• C1
• D0

• A
  77% (24)
• B
  6% (2)
• C
  3% (1)
• D
  13% (4)

Explanation

range(2) yields only 0 and 1, so the list comprehension produces exactly two inner lists - valid indices are 0 and 1 only. Accessing data[2] raises an IndexError at runtime, making the code erroneous (A correct).

Why the distractors fail:

• D (0) - A plausible trap: data[0][0] would be 0, but the outer index here is 2, not 0.
• B (2) - Another index confusion: data[0][2] would be 2, but again, the outer index 2 is out of range before the inner index is ever reached.
• C (1) - No valid index combination in this structure produces 1 from data[x][0]; the first element of every inner list is 0.

Memory tip: When you see range(n) in a list comprehension, the resulting list has exactly n elements (indices 0 through n-1). Here, range(2) → 2 elements → max index is 1, so any access at index 2 or higher will always crash.

No community discussion yet for this question.