What is the expected output of the following code? data = {'1': '0', '0': '1'} for d in data.vals(): print(d, end='')

The correct answer is C. The code is erroneous. Option C is correct because data.vals() is not a valid Python method - dictionaries use .values() (with a full "values"), so this code raises an AttributeError at runtime before any output is produced. Options A, B, and D all assume the code runs successfully, which it cannot…

Question

What is the expected output of the following code?
data = {'1': '0', '0': '1'}
for d in data.vals():
print(d, end='')

Options

A01
B10
CThe code is erroneous.
D00

How the community answered

(47 responses)

A
4% (2)
B
9% (4)
C
72% (34)
D
15% (7)

Explanation

Option C is correct because data.vals() is not a valid Python method - dictionaries use .values() (with a full "values"), so this code raises an AttributeError at runtime before any output is produced.

Options A, B, and D all assume the code runs successfully, which it cannot. If the typo were fixed to .values(), Python 3.7+ preserves insertion order, so the values '0' then '1' would print as 01 (making A the would-be correct answer) - not 10 (B) or 00 (D), which don't match the dict's values in any order.

Memory tip: Remember the full word - .keys(), .values(), .items() - Python dict methods are never abbreviated. If you see .vals(), .keys2(), or similar shorthand on an exam, it's always a trap for "erroneous code."

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