Assuming that the following assignment has been successfully executed: the_list = ['list', False, 3e8] Which of the following expressions evaluate to True? (Choose two.)

The correct answer is B. the_list[1] in the list. Option B evaluates to True because the_list[1] is False, and since False is literally stored in the list, False in the_list returns True. Note the question says choose two - D is also correct: the_list.index(False) scans left to right using ==; 'list' == False is False, so it…

Question

Assuming that the following assignment has been successfully executed:
the_list = ['list', False, 3e8]
Which of the following expressions evaluate to True? (Choose two.)

Options

Aint(the_list[2]) == len(the_list)
Bthe_list[1] in the list
C300 in the_list and the_list[1]
Dthe_list.index(False) == 1

How the community answered

(21 responses)

A
10% (2)
B
81% (17)
C
5% (1)
D
5% (1)

Explanation

Option B evaluates to True because the_list[1] is False, and since False is literally stored in the list, False in the_list returns True. Note the question says choose two - D is also correct: the_list.index(False) scans left to right using ==; 'list' == False is False, so it skips index 0, then finds False == False at index 1 and returns 1, making 1 == 1 → True.

A is wrong because int(the_list[2]) = int(3e8) = 300,000,000, which is not equal to len(the_list) = 3.

C is wrong because 3e8 is 300,000,000 - not 300 - so 300 in the_list is False; the and short-circuits and the entire expression is False regardless of the_list[1].

Memory tip: 3e8 means 3 × 10⁸ = 300,000,000 - the e is scientific notation, not shorthand for a small number. Whenever you see eN in a float, mentally multiply by 10^N before checking membership or equality.

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