What is the output of the following snippet? ``python my_list_1 = [1, 2, 3] my_list_2 = [] for v in my_list_1: my_list_2.insert(0, v) print(my_list_2) ``

Question

my_list_1 = [1, 2, 3]
my_list_2 = []
for v in my_list_1:
 my_list_2.insert(0, v)
print(my_list_2)

Options

• A[1, 2, 3]
• B[3, 2, 1]
• C[3, 2, 1]
• D[1, 1, 1]

• A
  4% (1)
• B
  76% (19)
• C
  12% (3)
• D
  8% (2)

Explanation

list.insert(0, v) always places each new value at index 0 (the front), pushing everything else right. Iterating [1, 2, 3] in order gives: [1] → [2, 1] → [3, 2, 1], so B is correct.

• A [1, 2, 3] is wrong - that's what you'd get using .append(v) (adds to the end), not .insert(0, v).
• C [3, 2, 1] is a deliberate duplicate of B included as a trap; since B appears first and is the labeled correct answer, C is the distractor.
• D [1, 1, 1] is wrong - nothing in the code repeats a single value; each element of my_list_1 is inserted exactly once.

Memory tip: Think of .insert(0, v) as "cutting to the front of the line" - the last person to arrive ends up first, so the final list is the reverse of the original.

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