What is the expected output of the following code? print(type(+1E10)) print(type(5.0)) print(type('True')) print(type(False))

Question

Options

• A<class 'float'> <class 'float'> <class 'str'> <class 'bool'>
• B<class 'int'> <class 'float'> <class 'bool'> <class 'bool'>
• C<class 'int'> <class 'float'> <class 'str'> <class 'bool'>
• D<class 'float'> <class 'float'> <class 'bool'> <class 'bool'>

• A
  85% (39)
• B
  2% (1)
• C
  4% (2)
• D
  9% (4)

Explanation

Option A is correct because Python treats any number written in scientific notation (like 1E10) as a float, regardless of the leading + sign - the result has no decimal point visually, but it's still a floating-point value. 5.0 is unambiguously a float, 'True' is a str because the quotes make it a string literal rather than a boolean, and False (capital F, no quotes) is Python's built-in boolean literal, giving bool.

Why the distractors fail:

• B and C both claim +1E10 is int, but scientific notation always produces a float in Python - you can verify with type(1E0).
• D claims 'True' is bool, but quotes always create a str; only the bare keywords True and False (no quotes) produce a bool.

Memory tip: Use the phrase "Quotes kill the bool" - any value wrapped in quotes is a str, no matter how boolean-looking it is. And remember "E means float" - scientific notation (E or e) always produces a float, never an int.

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