You want to print each name of the list on a new line. data = ['Peter', 'Paul', 'Mary', 'Jane'] Which statement will you use?

The correct answer is B. print('\n'.join(data)). Option B is correct because '\n'.join(data) is the standard Python idiom: the join() method belongs to strings, not lists, and takes an iterable as its argument - it inserts the string ('\n') between each element of data, producing Peter\nPaul\nMary\nJane. Why the others fail…

Question

You want to print each name of the list on a new line.
data = ['Peter', 'Paul', 'Mary', 'Jane']
Which statement will you use?

Options

Aprint(data.concatenate('\n'))
Bprint('\n'.join(data))
Cprint(data.join('\n'))
Dprint(data.join('%s\n', names))

How the community answered

(50 responses)

A
6% (3)
B
78% (39)
C
4% (2)
D
12% (6)

Explanation

Option B is correct because '\n'.join(data) is the standard Python idiom: the join() method belongs to strings, not lists, and takes an iterable as its argument - it inserts the string ('\n') between each element of data, producing Peter\nPaul\nMary\nJane.

Why the others fail:

A - list.concatenate() doesn't exist in Python; lists have no such method.
C - join() is a string method, not a list method; data.join(...) would raise an AttributeError.
D - Same problem as C (calling join on a list), plus join() takes one argument (an iterable), not a format string and a variable.

Memory tip: Think of it as "the glue goes first." Whatever you want between items - ',', ' ', '\n' - is the string you call .join() on, and the list is passed into it. If you ever write list.join(separator), flip it around.

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