Consider the following code snippet: 1 w = bool(23) 2 x = bool('') 3 y = bool(' ') 4 z = bool([False]) Which of the variables will contain False?

Question

Options

• Az
• Bw
• Cx
• Dy

• A
  15% (5)
• B
  9% (3)
• C
  73% (24)
• D
  3% (1)

Explanation

x contains False because bool('') evaluates an empty string, and in Python, empty containers and sequences (empty string, list, dict, tuple) are always falsy.

Why the distractors are wrong:

• A (z): bool([False]) evaluates to True - the list contains False, but the list itself is non-empty, and any non-empty collection is truthy. Python checks the container, not its contents.
• B (w): bool(23) is True - any non-zero number is truthy in Python.
• D (y): bool(' ') is True - a string with a space character is not empty; it has length 1, so it's truthy.

Memory tip: Python's falsy values follow an "empty or nothing" rule - 0, '', [], {}, None, and False itself are all falsy. A single space ' ' is a character, not nothing, so it passes. And remember: bool([False]) tricks many - Python doesn't peek inside the list, it just asks "does this list exist and have items?"

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