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PCEP-30-02 · Question #251

The following code: print(float("1", "3"))

The correct answer is D. raises a ValueError exception. Option D is the closest correct answer because float() accepts only one argument, so passing two strings ("1" and "3") raises an exception - though technically a TypeError ("float() takes at most 1 argument (2 given)"), not a ValueError. A ValueError would occur if you passed a…

Question

The following code: print(float("1", "3"))

Options

  • Aprints 13
  • Bprints 1,3
  • Cprints 1, 3
  • Draises a ValueError exception.

How the community answered

(29 responses)
  • A
    14% (4)
  • B
    7% (2)
  • C
    3% (1)
  • D
    76% (22)

Explanation

Option D is the closest correct answer because float() accepts only one argument, so passing two strings ("1" and "3") raises an exception - though technically a TypeError ("float() takes at most 1 argument (2 given)"), not a ValueError. A ValueError would occur if you passed a single non-numeric string like float("abc"). Options A and B are wrong because float() never concatenates or joins its arguments - that's not how the function works. Option C is similarly wrong for the same reason; no amount of formatting produces 1, 3 from this call.

Memory tip: Think of float() like a single-seat car - it can carry exactly one passenger (a string or number). Trying to squeeze in two passengers causes a crash (exception) before it even moves.

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