What is the expected output of the following code? print('x', 'y', 'z', sep='sep')

Question

Options

• Ax y z
• Bxyz
• Cxsepysepz
• Dxsepysepz

• A
  15% (3)
• B
  5% (1)
• C
  5% (1)
• D
  75% (15)

Explanation

Option D is correct because Python's print() function uses the sep parameter as the separator string inserted between each argument, so print('x', 'y', 'z', sep='sep') joins the three strings with the literal text "sep", producing xsepysepz.

Option A (x y z) is wrong - that would be the output with the default sep=' ' (a single space), which applies only when no sep argument is provided. Option B (xyz) is wrong - that would require sep='' (an empty string), which concatenates without any separator. Option C is identical to D in wording here (likely a typo in the question), but in typical exam variants C often shows x sep y sep z with surrounding spaces - which would require spaces built into the separator string, like sep=' sep '.

Memory tip: Think of sep as the glue poured between items - whatever string you assign to sep is exactly what appears between each printed argument, no more and no less.

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