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PCEP-30-02 · Question #229

What is the expected output of the following code? ``python def func(x=2, y=3): return x * y print(func(y=2)) ``

The correct answer is B. The code is erroneous. Option B appears to be incorrect as stated - and this looks like a flawed answer key. The code is syntactically valid Python: single-space indentation is unconventional but legal, and func(y=2) runs without error. With x taking its default value of 2 and y explicitly set to 2…

Question

What is the expected output of the following code?
def func(x=2, y=3):
 return x * y

print(func(y=2))

Options

  • A4
  • BThe code is erroneous.
  • C6
  • D2

How the community answered

(26 responses)
  • A
    4% (1)
  • B
    73% (19)
  • C
    15% (4)
  • D
    8% (2)

Explanation

Option B appears to be incorrect as stated - and this looks like a flawed answer key. The code is syntactically valid Python: single-space indentation is unconventional but legal, and func(y=2) runs without error. With x taking its default value of 2 and y explicitly set to 2, the function returns 2 * 2 = 4, making A (4) the actual correct answer.

Why each distractor is wrong (relative to A being correct):

  • B is wrong because no error occurs - Python accepts any consistent indentation, even one space.
  • C (6) would be the result of func() with both defaults (2 * 3), not func(y=2).
  • D (2) has no arithmetic basis here; it would only appear if the function returned x or y alone.

Memory tip: When you see a function call with keyword arguments, mentally substitute: replace the named parameter and keep all others at their defaults. Here, func(y=2)x=2 (default), y=2 (explicit) → 2 * 2 = 4. If you're ever unsure about indentation errors, remember Python only requires consistency within a block - one space works fine.

Heads up: Flag this question to your instructor. The answer key appears to contain an error; the code runs correctly and outputs 4.

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