What is the output of the following snippet? ``python def fun(inp=2, out=3): return inp * out print(fun(out=2)) ``

Question

def fun(inp=2, out=3):
 return inp * out

print(fun(out=2))

Options

• A2
• BThe snippet is erroneous
• C4
• D6

• A
  5% (2)
• B
  3% (1)
• C
  82% (32)
• D
  10% (4)

Explanation

Calling fun(out=2) uses the keyword argument to override only out, leaving inp at its default value of 2, so the function computes 2 * 2 = 4, making C correct.

A (2) is wrong because neither parameter equals 1 - there's no way to get a product of 2 from these values in this call. B is wrong because the code is perfectly valid Python; keyword arguments can be passed in any order and can override any subset of defaults. D (6) is the trap: that's what fun() returns with no arguments (2 * 3 = 6), but here out is explicitly changed to 2.

Memory tip: When you see a keyword argument call, mentally "apply the override, freeze the rest" - only the named parameter changes; every unnamed parameter stays at its default.

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