``python def fun(n): x = [] for i in range(n): x.append(i) return x print(fun(4)) `` What is the expected output of the following code?

Question

def fun(n):
 x = []
 for i in range(n):
 x.append(i)
 return x

print(fun(4))

Options

• A[4, 4, 4, 4]
• B0 1 2 3
• C[0, 1, 2, 3]
• DThe program will cause an error.

• A
  3% (1)
• B
  14% (5)
• C
  73% (27)
• D
  11% (4)

Explanation

Option C is correct because range(4) generates the sequence 0, 1, 2, 3 - starting at 0 and stopping before 4 - and each value is appended one by one to the list x, which is returned and printed as [0, 1, 2, 3]. Option A is wrong because no value is ever repeated or set to 4; each iteration appends a different i. Option B describes what you'd see if print(i) were called inside the loop on each iteration, not what happens when a completed list is returned and printed once. Option D is wrong because the code is syntactically and logically valid - there is no error.

Memory tip: Think of range(n) as a countdown that never reaches n - it always starts at 0 and stops at n-1, giving you exactly n values.

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