``python def func(x): global y y = x * x return y func(2) print(y) `` What is the expected output of the following code?

Question

def func(x):
 global y
 y = x * x
 return y

func(2)
print(y)

Options

• A2
• BNone
• CThe code is erroneous.
• D4

• A
  5% (2)
• B
  5% (2)
• C
  17% (7)
• D
  74% (31)

Explanation

Option D (4) is correct because the global y declaration inside func causes the assignment y = x * x (i.e., 2 * 2 = 4) to write into the global scope rather than a local one, so y persists after the function returns and print(y) outputs 4.

Option A (2) is wrong because x * x where x = 2 evaluates to 4, not 2 - squaring, not doubling. Option B (None) is wrong because without global y, the variable would be local and print(y) would raise a NameError; the global keyword is precisely what makes y visible outside the function. Option C is wrong because global y is perfectly valid Python syntax - you don't need to declare y globally before the function runs; the assignment inside the function creates it.

Memory tip: Think of global as "broadcasting" a variable from inside a function to the entire module - once set, anyone outside can read it, just like a global announcement.

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