What is the expected output of the following code? data = {} def func(d, key, value): d[key] = value print(func(data, '1', 'Peter'))

The correct answer is C. None. func modifies the dictionary in place but has no return statement - so it implicitly returns None. Since print() prints the return value of func(...), not what the function does internally, the output is None. Why each distractor fails: A (1) - '1' is the key argument passed…

Question

What is the expected output of the following code?
data = {}
def func(d, key, value):
d[key] = value
print(func(data, '1', 'Peter'))

Options

A1
BPeter
CNone
Dvalue
EThe code is erroneous.

How the community answered

(16 responses)

A
13% (2)
B
6% (1)
C
81% (13)

Explanation

func modifies the dictionary in place but has no return statement - so it implicitly returns None. Since print() prints the return value of func(...), not what the function does internally, the output is None.

Why each distractor fails:

A (1) - '1' is the key argument passed in, never returned or printed directly.
B (Peter) - 'Peter' gets stored in the dict (data['1'] = 'Peter'), but that assignment isn't returned; it's a side effect.
D (value) - value is just a parameter name in the function signature, not a meaningful output.
E (erroneous) - the code runs without error; data is successfully mutated, making this a common trap for those who confuse "works" with "returns something useful."

Memory tip: In Python, every function returns None unless you explicitly write return <something>. When you see print(some_function(...)), ask yourself: "does that function have a return statement?" If not, you're always printing None.

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