What is the expected output of the following code? def func(x=2, y=3): return x * y print(func(y=2))

The correct answer is A. 4. Option A (4) is correct because calling func(y=2) passes 2 explicitly for y, while x falls back to its default value of 2 - so the function returns 2 2 = 4. B is wrong because the code is perfectly valid Python; keyword arguments like y=2 are a core language feature that lets…

Question

What is the expected output of the following code?
def func(x=2, y=3):
return x * y
print(func(y=2))

Options

A4
BThe code is erroneous.
C6
D2

How the community answered

(29 responses)

A
76% (22)
B
7% (2)
C
3% (1)
D
14% (4)

Explanation

Option A (4) is correct because calling func(y=2) passes 2 explicitly for y, while x falls back to its default value of 2 - so the function returns 2 * 2 = 4.

B is wrong because the code is perfectly valid Python; keyword arguments like y=2 are a core language feature that lets callers override specific defaults without touching others. C (6) is the trap - it's what you'd get from func() with no arguments, using both defaults (2 * 3), a mistake made by forgetting that y was overridden. D (2) has no basis in the math; it might tempt someone who only looks at the passed argument value in isolation.

Memory tip: Think of default parameters as "factory settings" - calling with a keyword argument like y=2 only changes that one setting; every untouched parameter keeps its factory default. When in doubt, mentally substitute: x=2 (default, unchanged), y=2 (overridden) → 2 × 2 = 4.

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