What is the expected output of the following code? ``python 1 nums = [1, 2, 3] 2 data = ('Peter', ) * (len(nums) - nums[::-1][0]) 3 print(data) ``

Question

1 nums = [1, 2, 3]
2 data = ('Peter', ) * (len(nums) - nums[::-1][0])
3 print(data)

Options

• A('Peter', 'Peter')
• BPeterPeter
• CThe code is erroneous.
• D('Peter')
• E()

• A
  12% (3)
• C
  4% (1)
• D
  8% (2)
• E
  76% (19)

Explanation

Option E is correct because nums[::-1] reverses the list to [3, 2, 1], making nums[::-1][0] equal to 3. Subtracting this from len(nums) (also 3) gives 3 - 3 = 0, so ('Peter',) * 0 evaluates to an empty tuple ().

Why each distractor fails:

• A (('Peter', 'Peter')) requires a multiplier of 2, not 0.
• B (PeterPeter) is impossible - multiplying a tuple never produces a bare string output.
• C (erroneous) is wrong - the code runs without error; Python happily multiplies a tuple by 0.
• D (('Peter')) would require a multiplier of 1, and ('Peter') is actually just the string 'Peter' anyway - a single-element tuple needs the trailing comma: ('Peter',).

Memory tip: When you see a tuple multiplied by an expression, evaluate the expression first - if it resolves to 0, the result is always (), regardless of what's inside the tuple.

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