What is the expected output of the following code? def fun(): return 3 def add(n): return fun() + n print(add(3))

Question

Options

• A9
• BThe program will cause an error.
• C3
• D6

• A
  13% (5)
• B
  8% (3)
• C
  3% (1)
• D
  76% (29)

Explanation

D is correct because add(3) evaluates fun() + n, where fun() always returns the literal 3 and n is the argument 3, making the expression 3 + 3 = 6.

Why the distractors fail:

• A (9): Confuses addition with multiplication - 3 × 3 = 9, but the + operator is used, not *.
• B (error): Both functions are defined before they're called, and fun() requires no arguments, so Python has no complaint.
• C (3): Would be the result if add returned only fun() and ignored n, but the + n is always included.

Memory tip: When a function calls another function, substitute the called function's return value first, then finish the math - treat fun() like a variable that holds 3, so fun() + n becomes 3 + 3.

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