What is the expected output of the following code? ``python def func(data): for d in data[::2]: yield d for x in func('abcdef'): print(x, end='') ``

Question

def func(data):
 for d in data[::2]:
 yield d

for x in func('abcdef'):
 print(x, end='')

Options

• Aace
• Bbdf
• Cabcdef
• DAn empty line.

• A
  77% (24)
• B
  6% (2)
• C
  13% (4)
• D
  3% (1)

Explanation

Option A is correct because data[::2] slices the string 'abcdef' with a step of 2, selecting characters at indices 0, 2, and 4 - which are 'a', 'c', and 'e' - and yield turns func into a generator that produces each one, printed without a separator via end=''.

B (bdf) is wrong because that result requires data[1::2] (starting at index 1, the odd-indexed characters); the step-2 slice here starts at index 0 by default.

C (abcdef) is wrong because that would require no slicing at all (or data[::1]); the [::2] step skips every other character.

D (empty line) is wrong because the generator does produce values - yield inside a for loop over a non-empty slice will always yield at least one element when the iterable has content.

Memory tip: Read [::2] as "every 2nd item starting from the beginning (index 0)" - it always picks even-indexed positions (0, 2, 4…), giving you the odd-positioned characters in everyday 1-based counting.

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