What is the expected output of the following code? `` num = 2 + 3 * 5 print(Num) ``

Question

num = 2 + 3 * 5
print(Num)

Options

• A25
• B17.0
• CThe code is erroneous.
• D17

• A
  4% (1)
• B
  4% (1)
• C
  80% (20)
• D
  12% (3)

Explanation

Option C is correct because Python is case-sensitive - the variable is assigned as num (lowercase), but print(Num) references Num (uppercase N), which was never defined. This raises a NameError at runtime before any output is produced.

Why the distractors are wrong:

• D (17) would be the arithmetic result if the variable name were consistent, since Python follows standard operator precedence (multiplication before addition: 3 × 5 = 15, then 2 + 15 = 17) - but the code never reaches print successfully.
• A (25) incorrectly applies left-to-right evaluation (2 + 3) × 5 = 25, ignoring that * has higher precedence than +.
• B (17.0) makes the same precedence error as D and also wrongly assumes the result is a float - all operands are integers, so the result would be int, not float.

Memory tip: Think "Python reads variable names like a strict teacher - num and Num are completely different names. Always check that the variable you assign and the one you use match exactly in case."

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