You have the following le. index.py: from sys import argv\nsum = 0\nfor i in range(2, len(argv)):\n sum += float(argv[i])\nprint(\n \"The average score for {0} is {1:.2f}\"\n .format(argv[1]…

Question

Options

• Apython index.py Peter 100
• Bpython index.py Peter 100 200 300
• CThe code is erroneous.
• Dpython index.py Peter 100 200

• A
  5% (2)
• B
  71% (27)
• C
  16% (6)
• D
  8% (3)

Explanation

Option B is correct because passing 100 200 300 as scores gives a sum of 600 divided by 3 scores (len(argv)-2 = 5-2 = 3), which equals exactly 200.00 - matching the required output with "Peter" as argv[1].

Option A fails because a single score of 100 divided by 1 yields 100.00, not 200.00. Option D fails because (100+200)/2 = 150.00, still not 200.00. Option C is wrong because the code is valid Python that runs without errors.

Memory tip: Remember that argv[0] is always the script name, so scores start at index 2 - count your arguments carefully by working backwards from the desired average to find what inputs produce it.

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