What is the expected output of the following code? ``python data1 = '1', '2' data2 = ('3', '4') print(data1 + data2) ``

Question

data1 = '1', '2'
data2 = ('3', '4')
print(data1 + data2)

Options

• A['1', '2', '3', '4']
• B(1, 2, 3, 4)
• C('1', '2', '3', '4')
• DThe code is erroneous.

• A
  16% (7)
• B
  7% (3)
• C
  74% (32)
• D
  2% (1)

Explanation

Option C is correct because data1 = '1', '2' uses implicit tuple packing - Python treats a comma-separated sequence of values as a tuple even without parentheses, making data1 identical to ('1', '2'). Concatenating two tuples with + always produces a new tuple, so data1 + data2 yields ('1', '2', '3', '4').

Why the distractors fail:

• A is wrong because square brackets [] denote a list, not a tuple - + on two tuples never returns a list.
• B is wrong on two counts: the parentheses are correct for a tuple, but the values are string literals ('1', '2', etc.), so they print with quotes, not as bare integers.
• D is wrong because the code is perfectly valid Python - parentheses are optional when packing a tuple; the comma is what matters.

Memory tip: "The comma makes the tuple, not the parentheses." Whenever you see x = a, b in Python, read it as x = (a, b) - the parentheses are just for clarity, not syntax.

No community discussion yet for this question.