N10-005 · Question #340
A user reports that they are unable to connect to the network. Upon further investigation, a technician notices that the user has an IP address/subnet mask combination of 192.168.204.255/24. The…
The correct answer is C. 192.168.204.112/24. The IP address 192.168.204.255/24 is the broadcast address of the network and cannot be assigned to a host; a valid host address in the same /24 subnet as the gateway must be chosen.
Question
A user reports that they are unable to connect to the network. Upon further investigation, a technician notices that the user has an IP address/subnet mask combination of 192.168.204.255/24. The default gateway for the network is 192.168.204.254. Which of the following could the user's IP address be changed to so that they could connect to the network?
Options
- A192.168.204.0/27
- B192.168.204.1/27
- C192.168.204.112/24
- D192.168.204.254/24
How the community answered
(26 responses)- A4% (1)
- B4% (1)
- C85% (22)
- D8% (2)
Why each option
The IP address 192.168.204.255/24 is the broadcast address of the network and cannot be assigned to a host; a valid host address in the same /24 subnet as the gateway must be chosen.
192.168.204.0/27 is the network address of the 192.168.204.0/27 subnet and cannot be assigned to a host.
192.168.204.1/27 places the host in the /27 subnet (range .0-.31), which does not include the default gateway at .254, making the gateway unreachable.
192.168.204.112/24 is a valid host address within the 192.168.204.0/24 network, the same subnet as the default gateway at 192.168.204.254. The address is not a network address, broadcast address, or already-assigned gateway address, making it a usable and routable host IP.
192.168.204.254/24 is already assigned as the default gateway and assigning it to the user would create an IP conflict.
Concept tested: Valid host IP addressing and subnet boundaries
Source: https://learn.microsoft.com/en-us/troubleshoot/windows-client/networking/tcpip-addressing-and-subnetting
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