An 802.11n implementation is being discussed. Users are satisfied with the potential 300- 450 Mbps throughput of new 802.11n APs. Which three bandwidth requirements are used to calculate per client…

Question

Options

• A450 Mbps throughput is the client max for 5-GHz radio.
• BChannel bonding on 5 GHz is required for a client to have a 300 Mbps WiFi link.
• C300 Mbps throughput is the client max for 2.4-GHz radio.
• DThe remaining bandwidth is divided per device when more clients are connected to one AP.
• E100 Mbps Ethernet switch port is a potential bottleneck.
• FCleanAir helps clear noise for 802.11n channel bonding to work.

• A
  15% (7)
• B
  76% (35)
• C
  7% (3)
• F
  2% (1)

Explanation

Three bandwidth considerations for per-client throughput in an 802.11n deployment are: (B) Channel bonding (40 MHz channels) on 5 GHz is required to achieve a 300 Mbps PHY rate - without bonding, the maximum is ~150 Mbps on a single 20 MHz channel with 2 spatial streams; (D) The AP's wireless medium is shared - when multiple clients associate, total bandwidth is divided among them, so per-client throughput decreases as more devices connect; (E) A 100 Mbps Ethernet uplink on the AP is a wired bottleneck - even if the wireless link supports 300 Mbps, the AP's uplink to the switch caps aggregate throughput at 100 Mbps. Options A and C are incorrect because 450 Mbps requires 3×3:3 MIMO configurations, and 2.4 GHz channel bonding is generally avoided due to channel scarcity and interference.

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