What is the binary notation of the 192.168.3.24 IP address?

The correct answer is D. 11000000 10101000 00000011 00011000. Converting 192.168.3.24 to binary requires converting each octet independently, yielding 11000000.10101000.00000011.00011000.

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Question

Options

A10100000 10110010 11100011 00011001
B11000100 11101000 00000011 00010000
C11000000 11000001 11000101 11000111
D11000000 10101000 00000011 00011000

How the community answered

(33 responses)

A
3% (1)
C
6% (2)
D
91% (30)

Why each option

Converting 192.168.3.24 to binary requires converting each octet independently, yielding 11000000.10101000.00000011.00011000.

A10100000 10110010 11100011 00011001

The first octet 10100000 equals 160, not 192, making this address 160.178.227.25, which is incorrect.

B11000100 11101000 00000011 00010000

The first octet 11000100 equals 196, not 192, and the second octet 11101000 equals 232, not 168.

C11000000 11000001 11000101 11000111

Although the first octet 11000000 equals 192, the second octet 11000001 equals 193, not 168, making the full address incorrect.

D11000000 10101000 00000011 00011000Correct

192 = 128+64 = 11000000; 168 = 128+32+8 = 10101000; 3 = 00000011; 24 = 16+8 = 00011000. Each octet matches exactly, confirming D as the correct binary representation.

Concept tested: IPv4 decimal to binary octet conversion

Source: https://learn.microsoft.com/en-us/troubleshoot/windows-server/networking/tcpip-addressing-and-subnetting

Topics

#IPv4 addressing#binary notation#IP fundamentals

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