200-150 · Question #126
Given a subnet address of 10.6.128.0/22, how many IP addresses are usable for this subnet?
The correct answer is C. 1022. A /22 subnet has 1024 total IP addresses, but only 1022 are usable after reserving the network and broadcast addresses.
Question
Given a subnet address of 10.6.128.0/22, how many IP addresses are usable for this subnet?
Options
- A1024
- B2048
- C1022
- D2046
- E256
How the community answered
(38 responses)- A5% (2)
- B3% (1)
- C76% (29)
- D13% (5)
- E3% (1)
Why each option
A /22 subnet has 1024 total IP addresses, but only 1022 are usable after reserving the network and broadcast addresses.
1024 is the total address count for a /22, not the usable count, because it ignores the subtraction of the network and broadcast addresses.
2048 is the total address count for a /21 subnet (2^11), which has 11 host bits, not 10.
A /22 prefix leaves 10 host bits (32-22=10), yielding 2^10 = 1024 total addresses. Two addresses are always reserved - the network address (10.6.128.0) and the broadcast address (10.6.131.255) - leaving exactly 1022 usable host addresses.
2046 is the usable host count for a /21 subnet (2048-2), not a /22.
256 addresses corresponds to a /24 subnet (2^8 = 256), not a /22.
Concept tested: IPv4 /22 subnet usable host address calculation
Source: https://www.cisco.com/c/en/us/support/docs/ip/routing-information-protocol-rip/13788-3.html
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