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200-150 · Question #126

Given a subnet address of 10.6.128.0/22, how many IP addresses are usable for this subnet?

The correct answer is C. 1022. A /22 subnet has 1024 total IP addresses, but only 1022 are usable after reserving the network and broadcast addresses.

Cisco Data Center Networking Technologies

Question

Given a subnet address of 10.6.128.0/22, how many IP addresses are usable for this subnet?

Options

  • A1024
  • B2048
  • C1022
  • D2046
  • E256

How the community answered

(38 responses)
  • A
    5% (2)
  • B
    3% (1)
  • C
    76% (29)
  • D
    13% (5)
  • E
    3% (1)

Why each option

A /22 subnet has 1024 total IP addresses, but only 1022 are usable after reserving the network and broadcast addresses.

A1024

1024 is the total address count for a /22, not the usable count, because it ignores the subtraction of the network and broadcast addresses.

B2048

2048 is the total address count for a /21 subnet (2^11), which has 11 host bits, not 10.

C1022Correct

A /22 prefix leaves 10 host bits (32-22=10), yielding 2^10 = 1024 total addresses. Two addresses are always reserved - the network address (10.6.128.0) and the broadcast address (10.6.131.255) - leaving exactly 1022 usable host addresses.

D2046

2046 is the usable host count for a /21 subnet (2048-2), not a /22.

E256

256 addresses corresponds to a /24 subnet (2^8 = 256), not a /22.

Concept tested: IPv4 /22 subnet usable host address calculation

Source: https://www.cisco.com/c/en/us/support/docs/ip/routing-information-protocol-rip/13788-3.html

Topics

#subnetting#IPv4#CIDR#usable hosts

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