Given the code fragment: String flavors[] = {"Vanilla", "Chocolate"}; int choice = 2; switch (choice) { case 1: System.out.println("Selected " + flavors[1] + " flavor."); break; case 2…

Question

Options

• ASelected null flavor.
• BSelected Chocolate flavor.
• CAn ArrayIndexOutOfBoundsException is thrown at run time.
• DSelected Chocolate flavor. Thank you!

• A
  4% (2)
• B
  15% (7)
• C
  72% (34)
• D
  9% (4)

Explanation

Option C is correct because the array flavors has only two elements at indices 0 ("Vanilla") and 1 ("Chocolate") - valid indices are 0 and 1 only. When choice is 2, execution jumps to case 2, which attempts to access flavors[2], a non-existent index, causing an ArrayIndexOutOfBoundsException at runtime before any output is produced.

Options B and D (both say "Selected Chocolate flavor.") are wrong because "Chocolate" is at flavors[1], not flavors[2] - the code would need to read flavors[1] in case 2 to print that. Option A is wrong because Java throws an exception on an out-of-bounds access rather than returning null; null would only appear if the array slot itself held a null value.

Memory tip: Java arrays of size n have valid indices 0 through n-1. Whenever you see an array access, quickly check: length - 1 = last valid index. Here, length 2 means index 2 is always one too far.

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