Given the code fragment: List names = new ArrayList<>(); names.add("Julia"); names.add("Peter"); for (Iterator itr = names.iterator(); itr.hasNext();) { System.out.println(itr.next()); } What is the result?

B. A runtime exception is thrown.

Oracle

1Z0-811 · Question #17

1Z0-811 Question #17: Real Exam Question with Answer & Explanation

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Arrays and Logic

Question

Given the code fragment:
List<String> names = new ArrayList<>();
names.add("Julia");
names.add("Peter");
for (Iterator<String> itr = names.iterator(); itr.hasNext();) {
System.out.println(itr.next());
}
What is the result?

Options

AA compilation error occurs.
BA runtime exception is thrown.
CJulia Peter
DPeter Julia

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Topics

#Iterator#ArrayList#Collections API#Iteration Order

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