Given the code fragment: String[] codes = {"CA", "JP", "US", "CA", "UK"}; int count = 0; for (String c : codes) { if (c.equals("CA")) { continue; } else { count++; } } System.out.println (count)…

The correct answer is A. 3. Option A (3) is correct because continue skips the rest of the loop body for elements equal to "CA", so the two "CA" entries never reach count++. The remaining three elements - "JP", "US", and "UK" - each fall into the else branch and increment count once each, yielding 3…

Control Flow

Question

Given the code fragment:
String[] codes = {"CA", "JP", "US", "CA", "UK"};
int count = 0;
for (String c : codes) {
if (c.equals("CA")) {
continue;
} else {
count++;
}
}
System.out.println (count);
What is the result?

Options

A3
BA compilation error occurs.
C2
D0

How the community answered

(36 responses)

A
72% (26)
B
3% (1)
C
8% (3)
D
17% (6)

Explanation

Option A (3) is correct because continue skips the rest of the loop body for elements equal to "CA", so the two "CA" entries never reach count++. The remaining three elements - "JP", "US", and "UK" - each fall into the else branch and increment count once each, yielding 3. Option C (2) is a common trap: test-takers may mistakenly count only the distinct non-CA values or miscount the iterations. Option D (0) would only result if continue somehow blocked all increments, which it does not - it only skips iterations where the condition is true. Option B is wrong because the code is syntactically and semantically valid; continue is perfectly legal inside a for-each loop.

Memory tip: Think of continue as "skip this one and move on" - it skips only the current iteration, not the whole loop. Count how many elements do not match the continue condition, and that's your answer.

Topics

#continue statement#loop control flow#String.equals()#counter logic

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