101 · Question #534
An administrator is currently designing the IP addressing scheme for a small company. They have been asked to use the 192.168.100.x block of addresses with a /27 network prefix. How many networks and
The correct answer is C. 8 networks each with 30 hosts. A /27 prefix applied to a Class C 192.168.100.x block yields 8 subnets each supporting 30 usable host addresses.
Question
An administrator is currently designing the IP addressing scheme for a small company. They have been asked to use the 192.168.100.x block of addresses with a /27 network prefix. How many networks and hosts per network will be available when using the 27-bit network prefix?
Options
- A255 networks each with 224 hosts
- B30 networks each with 8 hosts
- C8 networks each with 30 hosts
- D27 networks each with 30 hosts
How the community answered
(30 responses)- A3% (1)
- B17% (5)
- C73% (22)
- D7% (2)
Why each option
A /27 prefix applied to a Class C 192.168.100.x block yields 8 subnets each supporting 30 usable host addresses.
255 networks with 224 hosts misrepresents the math entirely and does not correspond to any valid interpretation of a /27 mask on this address block.
30 networks with 8 hosts inverts the correct values - the /27 produces 8 subnets and 30 hosts, not the other way around.
With a /27 mask on a /24 Class C block, 3 bits are borrowed from the host portion (27 - 24 = 3), creating 2^3 = 8 subnets. Each subnet retains 5 host bits, giving 2^5 = 32 total addresses per subnet minus 2 (network and broadcast addresses) for 30 usable hosts per subnet.
27 networks is not a valid result because subnet counts must be a power of 2; the 3 borrowed bits yield exactly 8 subnets, not 27.
Concept tested: IPv4 CIDR subnetting calculation with /27 prefix
Source: https://www.cisco.com/c/en/us/support/docs/ip/routing-information-protocol/13788-3.html
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