SY0-501 · Question #42
SY0-501 Question #42: Real Exam Question with Answer & Explanation
The correct answer is B: 192.168.0.16/28. This question tests the ability to select the smallest subnet that can accommodate 14 physical hosts, minimizing wasted address space while meeting requirements.
Question
A security administrator is creating a subnet on one of the corporate firewall interfaces to use as a DMZ which is expected to accommodate at most 14 physical hosts. Which of the following subnets would BEST meet the requirements?
Options
- A192.168.0.16 255.25.255.248
- B192.168.0.16/28
- C192.168.1.50 255.255.25.240
- D192.168.2.32/27
Explanation
This question tests the ability to select the smallest subnet that can accommodate 14 physical hosts, minimizing wasted address space while meeting requirements.
Common mistakes.
- A. The subnet mask 255.25.255.248 is invalid - the second octet '25' is not a valid subnet mask value; valid octets in a subnet mask must follow a contiguous bit pattern (e.g., 255.255.255.248).
- C. The subnet mask 255.255.25.240 is also invalid because '25' in the third octet is not a legal subnet mask value, making this an unusable and incorrect subnet definition.
- D. A /27 prefix provides 32 total addresses with 30 usable hosts, which accommodates the 14-host requirement but wastes significantly more address space than a /28, making it a suboptimal choice when the question asks for the BEST fit.
Concept tested. Subnetting to meet minimum host requirements efficiently
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