SK0-003 · Question #682
An administrator installs a new server with five 146GB drives and implements RAID 5 for hardware redundancy. How much disk space will be available for the OS, tools and regular files?
The correct answer is C. 584GB. In a RAID 5 configuration, one drive's capacity is dedicated to parity information across all drives, so the total usable space is the sum of the capacities of the remaining drives.
Question
An administrator installs a new server with five 146GB drives and implements RAID 5 for hardware redundancy. How much disk space will be available for the OS, tools and regular files?
Options
- A146GB
- B438GB
- C584GB
- D730GB
How the community answered
(23 responses)- A9% (2)
- B4% (1)
- C74% (17)
- D13% (3)
Why each option
In a RAID 5 configuration, one drive's capacity is dedicated to parity information across all drives, so the total usable space is the sum of the capacities of the remaining drives.
146GB represents the capacity of a single drive, which is incorrect as the question refers to a 5-drive RAID 5 array.
438GB would be the usable capacity for a 4-drive RAID 5 array (3 * 146GB), not a 5-drive array.
RAID 5 requires one drive's worth of space for parity information across all drives to provide data redundancy. With five 146GB drives, the total usable capacity for data, OS, and tools is calculated as (Number of Drives - 1) * Drive Capacity, which is (5 - 1) * 146GB = 4 * 146GB = 584GB.
730GB is the total raw capacity of all five drives (5 * 146GB), but this does not account for the space reserved for parity in RAID 5.
Concept tested: RAID 5 usable capacity calculation
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