RCDD-002 · Question #18
An ICT distribution designer is estimating the installation of five units of 1.5 m (5 ft) tong channel basket trays connected together in the ceiling. The total length of the pathway needed is 7.5 m…
The correct answer is B. 5. Option B (5 supports) is correct because the standard rule for cable tray installation requires one support per tray unit. With five 1.5 m tray sections, you need exactly five supports - one for each unit, regardless of the total run length. Why the distractors are wrong: A (2)…
Question
An ICT distribution designer is estimating the installation of five units of 1.5 m (5 ft) tong channel basket trays connected together in the ceiling. The total length of the pathway needed is 7.5 m (25 ft). How many supports will be needed?
Options
- A2
- B5
- C7
- D10
- E20
How the community answered
(52 responses)- A2% (1)
- B73% (38)
- C4% (2)
- D15% (8)
- E6% (3)
Explanation
Option B (5 supports) is correct because the standard rule for cable tray installation requires one support per tray unit. With five 1.5 m tray sections, you need exactly five supports - one for each unit, regardless of the total run length.
Why the distractors are wrong:
- A (2) is tempting if you think only of the two endpoints of the run, but that ignores the intermediate tray sections that also require support.
- C (7) might arise if someone miscalculates by adding the number of connection joints (4) to the number of trays (5) minus a correction - there's no standard formula that produces 7 here.
- D (10) comes from incorrectly applying 2 supports per tray (5 × 2 = 10), which would be excessive and non-standard.
- E (20) likely results from confusing the unit length in feet (5 ft) with the count, multiplying 5 trays × 4 supports, or some other miscalculation unrelated to the standard.
Memory tip: Think "1 tray = 1 support." Just count the number of tray sections in the run - that number is always your answer when trays are connected end-to-end with no special spanning exceptions.
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