An Administrator wants to maximize the use of a network address. The network is 192.168.6.0/24 and there are three subnets that need to be created that can not overlap. Which subnet would you use…

The correct answer is B. 192.168.6.0/25. To support 120 hosts, you need a subnet with at least 120 usable host addresses. Using the formula 2^n − 2 (subtract network and broadcast addresses): a /25 prefix leaves 7 host bits → 2^7 − 2 = 126 usable hosts, which satisfies the 120-host requirement. 192.168.6.0/25 covers…

Submitted by neha2k· Apr 18, 2026Network Security

Question

An Administrator wants to maximize the use of a network address. The network is 192.168.6.0/24 and there are three subnets that need to be created that can not overlap. Which subnet would you use for the network with 120 hosts? Requirements for the three subnets:

Subnet 1: 3 host addresses Subnet 2: 25 host addresses Subnet 3: 120 host addresses

Options

A192.168.6.168/30
B192.168.6.0/25
C192.168.6.160/29
D192.168.6.128/27

How the community answered

(22 responses)

A
9% (2)
B
82% (18)
C
5% (1)
D
5% (1)

Explanation

To support 120 hosts, you need a subnet with at least 120 usable host addresses. Using the formula 2^n − 2 (subtract network and broadcast addresses): a /25 prefix leaves 7 host bits → 2^7 − 2 = 126 usable hosts, which satisfies the 120-host requirement. 192.168.6.0/25 covers addresses .0–.127 and provides 126 usable hosts. The other subnets handle the remaining requirements without overlap: 192.168.6.128/27 provides 30 hosts for Subnet 2 (25 hosts needed), and 192.168.6.160/29 provides 6 hosts for Subnet 1 (3 hosts needed). Option A (/30) gives only 2 usable hosts, D (/27) gives 30 usable hosts - sufficient for 25 but not the optimal fit for 120.

Topics

#Subnetting#VLSM#IP Addressing#Network Design

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