N10-005 · Question #824
Which of the following uses a 128-bit addressing scheme?
The correct answer is D. IPv6. IPv6 uses a 128-bit address space, represented as eight groups of four hexadecimal digits. This is the key differentiator from IPv4, which uses only 32 bits.
Question
Which of the following uses a 128-bit addressing scheme?
Options
- AMAC
- BDHCP
- CIPv4
- DIPv6
How the community answered
(57 responses)- A2% (1)
- B5% (3)
- C4% (2)
- D89% (51)
Why each option
IPv6 uses a 128-bit address space, represented as eight groups of four hexadecimal digits. This is the key differentiator from IPv4, which uses only 32 bits.
A MAC (Media Access Control) address is a 48-bit hardware identifier assigned to a network interface card, not a 128-bit addressing scheme.
DHCP (Dynamic Host Configuration Protocol) is a protocol for dynamically assigning IP addresses to clients; it is not itself an addressing scheme with a defined bit length.
IPv4 uses a 32-bit address space, which provides approximately 4.3 billion unique addresses - not 128 bits.
IPv6 was designed to replace IPv4 and dramatically expand the address space by using 128-bit addresses (compared to IPv4's 32 bits). A 128-bit address provides approximately 3.4 x 10^38 unique addresses, written in colon-separated hexadecimal notation, enabling virtually unlimited device addressing on a global scale.
Concept tested: IPv6 128-bit addressing scheme
Source: https://learn.microsoft.com/en-us/windows-server/networking/technologies/ipv6/ipv6-overview
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