ICGB · Question #27
What is the Cycle Time, in seconds, for a process having a Throughput of 7,200 units per hour?
The correct answer is A. 0.5. Option A (0.5 seconds) is correct because Cycle Time is the reciprocal of Throughput rate expressed in the same time unit. Converting 7,200 units/hour to seconds: 7,200 ÷ 3,600 seconds/hour = 2 units/second, and Cycle Time = 1 ÷ 2 = 0.5 seconds. Option B (2) is a common trap…
Question
What is the Cycle Time, in seconds, for a process having a Throughput of 7,200 units per hour?
Options
- A0.5
- B2
- C4
- D10
How the community answered
(41 responses)- A71% (29)
- B2% (1)
- C10% (4)
- D17% (7)
Explanation
Option A (0.5 seconds) is correct because Cycle Time is the reciprocal of Throughput rate expressed in the same time unit. Converting 7,200 units/hour to seconds: 7,200 ÷ 3,600 seconds/hour = 2 units/second, and Cycle Time = 1 ÷ 2 = 0.5 seconds.
Option B (2) is a common trap - it's the throughput rate in units/second (the intermediate conversion step), but candidates forget to take the reciprocal to get cycle time. Options C and D result from unit conversion errors, such as using incorrect values for seconds-per-hour or misapplying the formula altogether.
Memory tip: Think of it as CT = 1/R - "one over rate." Always convert throughput to the target time unit first (divide units/hour by 3,600 to get units/second), then flip it.
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