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ICGB · Question #27

What is the Cycle Time, in seconds, for a process having a Throughput of 7,200 units per hour?

The correct answer is A. 0.5. Option A (0.5 seconds) is correct because Cycle Time is the reciprocal of Throughput rate expressed in the same time unit. Converting 7,200 units/hour to seconds: 7,200 ÷ 3,600 seconds/hour = 2 units/second, and Cycle Time = 1 ÷ 2 = 0.5 seconds. Option B (2) is a common trap…

Measure

Question

What is the Cycle Time, in seconds, for a process having a Throughput of 7,200 units per hour?

Options

  • A0.5
  • B2
  • C4
  • D10

How the community answered

(41 responses)
  • A
    71% (29)
  • B
    2% (1)
  • C
    10% (4)
  • D
    17% (7)

Explanation

Option A (0.5 seconds) is correct because Cycle Time is the reciprocal of Throughput rate expressed in the same time unit. Converting 7,200 units/hour to seconds: 7,200 ÷ 3,600 seconds/hour = 2 units/second, and Cycle Time = 1 ÷ 2 = 0.5 seconds.

Option B (2) is a common trap - it's the throughput rate in units/second (the intermediate conversion step), but candidates forget to take the reciprocal to get cycle time. Options C and D result from unit conversion errors, such as using incorrect values for seconds-per-hour or misapplying the formula altogether.

Memory tip: Think of it as CT = 1/R - "one over rate." Always convert throughput to the target time unit first (divide units/hour by 3,600 to get units/second), then flip it.

Topics

#cycle time#throughput#process metrics#time calculation

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