H12-831_V1.0 · Question #181
In the network shown in the figure, R1, R2, R4, and R5 run IS-IS in area 49.0001, and R3 and R6 run IS-IS in area 49.0002. Within AS 65000, R1, R3, R4, and R6 establish IBGP neighbor relationships…
The correct answer is B. There are two equal default routes in R4's routing table. C. For 192.168.1.0/24, R3 prefers the BGP route received from R2, and R6 prefers the BGP route. See the full explanation below for the reasoning.
Question
In the network shown in the figure, R1, R2, R4, and R5 run IS-IS in area 49.0001, and R3 and R6 run IS-IS in area 49.0002. Within AS 65000, R1, R3, R4, and R6 establish IBGP neighbor relationships with R2 and R5, of which R2 and R5 are RRs and R1, R4, R3, and R6 are clients. IBGP neighbor relationships are all established using the Loopback0 interface. The IP address of the Loopback0 interface of each device is 10.0.X.X/32, and the Router ID is 10.0.X.X, where X is the device number. R1 and R4 introduce the external network 192.168.1.0/24 into BGP through import, and R3 and R6 introduce the external network 192.168.2.0/24 into BGP through import. Which of the following descriptions are correct by default? (Multiple choice)
Options
- AThere are two next hops for reaching 192.168.1.0/24 in R3's routing table.
- BThere are two equal default routes in R4's routing table.
- CFor 192.168.1.0/24, R3 prefers the BGP route received from R2, and R6 prefers the BGP route
- DThere is no route entry for 192.168.2.0/24 in R1's routing table.
How the community answered
(24 responses)- A4% (1)
- B83% (20)
- D13% (3)
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